Why does virtual memory require 2 35 entries?

Date:2023-01-06
To store a 4KB page of memory on a 32-bit system, you need 32 bits (4 bytes) of address space. With 2^35 entries, that means you can have up to 2^35 different 4KB pages of memory in the virtual address space. This is more than the amount of physical memory that can actually fit in the system, so it allows the operating system to efficiently use virtual memory to provide more resources to the applications running on the system.
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